What are the solutions to the equation x^2+50x+336=0 ?

The solutions to the equation x^2+50x+336=0 are x=-8,x=-42

Find the zeros of x^2+50x+336=0

The zeros of x^2+50x+336=0 are x=-8,x=-42

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x^{2} + 50 x + 336 = 0

x = - 8, x = - 42

Solution steps

x^{2} + 50 x + 336 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 1 \cdot 336}{2 \cdot 1}

5 0^{2} - 4 \cdot 1 \cdot 336 = 34

x_{1, 2} = \frac{- 50 \pm 34}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 50 + 34}{2 \cdot 1}, x_{2} = \frac{- 50 - 34}{2 \cdot 1}

x = \frac{- 50 + 34}{2 \cdot 1} : - 8

x = \frac{- 50 - 34}{2 \cdot 1} : - 42

The solutions to the quadratic equation are:

x = - 8, x = - 42

(x - 3)^{2} = x - 1

- 3 x^{2} + 4 x + 5 = 0

x^{2} - 28 x

x^{2} - 13 x

x^{2} - 15 x

What are the solutions to the equation x^2+50x+336=0 ?
The solutions to the equation x^2+50x+336=0 are x=-8,x=-42
Find the zeros of x^2+50x+336=0
The zeros of x^2+50x+336=0 are x=-8,x=-42