What are the solutions to the equation -3x^2+4x+5=0 ?

The solutions to the equation -3x^2+4x+5=0 are x=-(-2+sqrt(19))/3 ,x=(2+sqrt(19))/3

Find the zeros of -3x^2+4x+5=0

The zeros of -3x^2+4x+5=0 are x=-(-2+sqrt(19))/3 ,x=(2+sqrt(19))/3

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- 3 x^{2} + 4 x + 5 = 0

x = - \frac{- 2 + 19}{3}, x = \frac{2 + 19}{3}

Decimal Notation

x = - 0.78629 \dots, x = 2.11963 \dots

Solution steps

- 3 x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 3 ) \cdot 5}{2 ( - 3 )}

4^{2} - 4 (- 3) \cdot 5 = 219

x_{1, 2} = \frac{- 4 \pm 2 19}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 19}{2 ( - 3 )}, x_{2} = \frac{- 4 - 2 19}{2 ( - 3 )}

x = \frac{- 4 + 2 19}{2 ( - 3 )} : - \frac{- 2 + 19}{3}

x = \frac{- 4 - 2 19}{2 ( - 3 )} : \frac{2 + 19}{3}

The solutions to the quadratic equation are:

x = - \frac{- 2 + 19}{3}, x = \frac{2 + 19}{3}

x^{2} - 28 x

x^{2} - 13 x

x^{2} - 15 x

v^{2} - 8 v + 45 = 0

x^{2} - 12 x = 10

What are the solutions to the equation -3x^2+4x+5=0 ?
The solutions to the equation -3x^2+4x+5=0 are x=-(-2+sqrt(19))/3 ,x=(2+sqrt(19))/3
Find the zeros of -3x^2+4x+5=0
The zeros of -3x^2+4x+5=0 are x=-(-2+sqrt(19))/3 ,x=(2+sqrt(19))/3