What are the solutions to the equation x^2-12x=10 ?

The solutions to the equation x^2-12x=10 are x=6+sqrt(46),x=6-sqrt(46)

Find the zeros of x^2-12x=10

The zeros of x^2-12x=10 are x=6+sqrt(46),x=6-sqrt(46)

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x^{2} - 12 x = 10

x = 6 + 46, x = 6 - 46

Decimal Notation

x = 12.78232 \dots, x = - 0.78232 \dots

Solution steps

x^{2} - 12 x = 10

Move

10

to the left side

x^{2} - 12 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 10) = 246

x_{1, 2} = \frac{- ( - 12 ) \pm 2 46}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 46}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 46}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 46}{2 \cdot 1} : 6 + 46

x = \frac{- ( - 12 ) - 2 46}{2 \cdot 1} : 6 - 46

The solutions to the quadratic equation are:

x = 6 + 46, x = 6 - 46

5 x^{2} - 3 x + 5 = 0

3 x^{2} + x = 14

4 x^{2} + 8 x

0 = 3 x^{2} - 27

4 x^{2} + 6 x

What are the solutions to the equation x^2-12x=10 ?
The solutions to the equation x^2-12x=10 are x=6+sqrt(46),x=6-sqrt(46)
Find the zeros of x^2-12x=10
The zeros of x^2-12x=10 are x=6+sqrt(46),x=6-sqrt(46)