What are the solutions to the equation 3x^2+x=14 ?

The solutions to the equation 3x^2+x=14 are x=2,x=-7/3

Find the zeros of 3x^2+x=14

The zeros of 3x^2+x=14 are x=2,x=-7/3

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3 x^{2} + x = 14

x = 2, x = - \frac{7}{3}

Decimal Notation

x = 2, x = - 2.33333 \dots

Solution steps

3 x^{2} + x = 14

Move

14

to the left side

3 x^{2} + x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 14 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 14) = 13

x_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 13}{2 \cdot 3}, x_{2} = \frac{- 1 - 13}{2 \cdot 3}

x = \frac{- 1 + 13}{2 \cdot 3} : 2

x = \frac{- 1 - 13}{2 \cdot 3} : - \frac{7}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{7}{3}

4 x^{2} + 8 x

0 = 3 x^{2} - 27

4 x^{2} + 6 x

2 (t - 3)^{2} - 72 = 0

4.5 x = (2 x - 1)^{2}

What are the solutions to the equation 3x^2+x=14 ?
The solutions to the equation 3x^2+x=14 are x=2,x=-7/3
Find the zeros of 3x^2+x=14
The zeros of 3x^2+x=14 are x=2,x=-7/3