What are the solutions to the equation 2(t-3)^2-72=0 ?

The solutions to the equation 2(t-3)^2-72=0 are t=9,t=-3

Find the zeros of 2(t-3)^2-72=0

The zeros of 2(t-3)^2-72=0 are t=9,t=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 (t - 3)^{2} - 72 = 0

t = 9, t = - 3

Solution steps

2 (t - 3)^{2} - 72 = 0

Move

72

to the right side

2 (t - 3)^{2} = 72

Divide both sides by

2

(t - 3)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t - 3 = 36 : t = 9

Solve

t - 3 = - 36 : t = - 3

The solutions to the quadratic equation are:

t = 9, t = - 3

4.5 x = (2 x - 1)^{2}

5 x^{2} - 10 x - 255 = 0

8 x^{2} - x - 9 = 0

x^{2} - 5 x + \frac{9}{4} = 0

- 4 x^{2} + 2 x = 0

What are the solutions to the equation 2(t-3)^2-72=0 ?
The solutions to the equation 2(t-3)^2-72=0 are t=9,t=-3
Find the zeros of 2(t-3)^2-72=0
The zeros of 2(t-3)^2-72=0 are t=9,t=-3