What are the solutions to the equation x^2-5x+9/4 =0 ?

The solutions to the equation x^2-5x+9/4 =0 are x= 9/2 ,x= 1/2

Find the zeros of x^2-5x+9/4 =0

The zeros of x^2-5x+9/4 =0 are x= 9/2 ,x= 1/2

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x^{2} - 5 x + \frac{9}{4} = 0

x = \frac{9}{2}, x = \frac{1}{2}

Decimal Notation

x = 4.5, x = 0.5

Solution steps

x^{2} - 5 x + \frac{9}{4} = 0

Multiply both sides by

4

4 x^{2} - 20 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 9 = 16

x_{1, 2} = \frac{- ( - 20 ) \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 16}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 16}{2 \cdot 4}

x = \frac{- ( - 20 ) + 16}{2 \cdot 4} : \frac{9}{2}

x = \frac{- ( - 20 ) - 16}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = \frac{1}{2}

- 4 x^{2} + 2 x = 0

2 x^{2} + 6 x + 12 = 0

6 x^{2} - 9 x + 3 = 0

x, (x - 4)^{2} \frac{- ( y + 5 ) 2}{3} = 1

2^{2} + x^{2} = 7^{2}

What are the solutions to the equation x^2-5x+9/4 =0 ?
The solutions to the equation x^2-5x+9/4 =0 are x= 9/2 ,x= 1/2
Find the zeros of x^2-5x+9/4 =0
The zeros of x^2-5x+9/4 =0 are x= 9/2 ,x= 1/2