What are the solutions to the equation 2x^2+6x+12=0 ?

The solutions to the equation 2x^2+6x+12=0 are x=-3/2+i(sqrt(15))/2 ,x=-3/2-i(sqrt(15))/2

Find the zeros of 2x^2+6x+12=0

The zeros of 2x^2+6x+12=0 are x=-3/2+i(sqrt(15))/2 ,x=-3/2-i(sqrt(15))/2

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2 x^{2} + 6 x + 12 = 0

x = - \frac{3}{2} + i \frac{15}{2}, x = - \frac{3}{2} - i \frac{15}{2}

Solution steps

2 x^{2} + 6 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

Simplify

6^{2} - 4 \cdot 2 \cdot 12 : 215 i

x_{1, 2} = \frac{- 6 \pm 2 15 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 15 i}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 15 i}{2 \cdot 2}

x = \frac{- 6 + 2 15 i}{2 \cdot 2} : - \frac{3}{2} + i \frac{15}{2}

x = \frac{- 6 - 2 15 i}{2 \cdot 2} : - \frac{3}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{15}{2}, x = - \frac{3}{2} - i \frac{15}{2}

6 x^{2} - 9 x + 3 = 0

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2^{2} + x^{2} = 7^{2}

\frac{x ^{2}}{25} + \frac{x ^{2}}{16} = 1

- 3 x^{2} - 10 x + 4 = 0

What are the solutions to the equation 2x^2+6x+12=0 ?
The solutions to the equation 2x^2+6x+12=0 are x=-3/2+i(sqrt(15))/2 ,x=-3/2-i(sqrt(15))/2
Find the zeros of 2x^2+6x+12=0
The zeros of 2x^2+6x+12=0 are x=-3/2+i(sqrt(15))/2 ,x=-3/2-i(sqrt(15))/2