What are the solutions to the equation 4(2x+4)^2+42=46 ?

The solutions to the equation 4(2x+4)^2+42=46 are x=-3/2 ,x=-5/2

Find the zeros of 4(2x+4)^2+42=46

The zeros of 4(2x+4)^2+42=46 are x=-3/2 ,x=-5/2

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4 (2 x + 4)^{2} + 42 = 46

x = - \frac{3}{2}, x = - \frac{5}{2}

Decimal Notation

x = - 1.5, x = - 2.5

Solution steps

4 (2 x + 4)^{2} + 42 = 46

Move

42

to the right side

4 (2 x + 4)^{2} = 4

Divide both sides by

4

(2 x + 4)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 4 = 1 : x = - \frac{3}{2}

Solve

2 x + 4 = - 1 : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - \frac{5}{2}

x, x^{2} + x y - y^{3} = - 1

12 x^{2} - 22 x + 6 = 0

5 x^{2} - 11 x - 2 = 0

x^{2} + 4 x - 30 = 0

x^{2} + 3 x - 40 = 0

What are the solutions to the equation 4(2x+4)^2+42=46 ?
The solutions to the equation 4(2x+4)^2+42=46 are x=-3/2 ,x=-5/2
Find the zeros of 4(2x+4)^2+42=46
The zeros of 4(2x+4)^2+42=46 are x=-3/2 ,x=-5/2