What are the solutions to the equation 7x^2+19x-6=0 ?

The solutions to the equation 7x^2+19x-6=0 are x= 2/7 ,x=-3

Find the zeros of 7x^2+19x-6=0

The zeros of 7x^2+19x-6=0 are x= 2/7 ,x=-3

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7 x^{2} + 19 x - 6 = 0

x = \frac{2}{7}, x = - 3

Decimal Notation

x = 0.28571 \dots, x = - 3

Solution steps

7 x^{2} + 19 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 7 ( - 6 )}{2 \cdot 7}

1 9^{2} - 4 \cdot 7 (- 6) = 23

x_{1, 2} = \frac{- 19 \pm 23}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 19 + 23}{2 \cdot 7}, x_{2} = \frac{- 19 - 23}{2 \cdot 7}

x = \frac{- 19 + 23}{2 \cdot 7} : \frac{2}{7}

x = \frac{- 19 - 23}{2 \cdot 7} : - 3

The solutions to the quadratic equation are:

x = \frac{2}{7}, x = - 3

x, (y - 1)^{2} = (x + 2)^{2}

9^{2} + b^{2} = 1 0^{2}

12 x^{2} - 4 x - 5 = 0

48 = x^{2} + 8 x

- 5 m^{2} = - 6 m

What are the solutions to the equation 7x^2+19x-6=0 ?
The solutions to the equation 7x^2+19x-6=0 are x= 2/7 ,x=-3
Find the zeros of 7x^2+19x-6=0
The zeros of 7x^2+19x-6=0 are x= 2/7 ,x=-3