What are the solutions to the equation solvefor x,y^2+4x^2+16=0 ?

The solutions to the equation solvefor x,y^2+4x^2+16=0 are x=(sqrt(-y^2-16))/2 ,x=-(sqrt(-y^2-16))/2

Find the zeros of solvefor x,y^2+4x^2+16=0

The zeros of solvefor x,y^2+4x^2+16=0 are x=(sqrt(-y^2-16))/2 ,x=-(sqrt(-y^2-16))/2

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solve for

x, y^{2} + 4 x^{2} + 16 = 0

x = \frac{- y ^{2} - 16}{2}, x = - \frac{- y ^{2} - 16}{2}

Solution steps

y^{2} + 4 x^{2} + 16 = 0

Move

y^{2}

to the right side

4 x^{2} + 16 = - y^{2}

Move

16

to the right side

4 x^{2} = - y^{2} - 16

Divide both sides by

4

x^{2} = \frac{- y ^{2} - 16}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{- y ^{2} - 16}{4}, x = - \frac{- y ^{2} - 16}{4}

Simplify

\frac{- y ^{2} - 16}{4} : \frac{- y ^{2} - 16}{2}

Simplify

- \frac{- y ^{2} - 16}{4} : - \frac{- y ^{2} - 16}{2}

x = \frac{- y ^{2} - 16}{2}, x = - \frac{- y ^{2} - 16}{2}

4 t^{2} + 3 t + 2 = 0

x, 7 x^{2} - 63 x y + 13 y^{2} - 16 = 0

x, x^{2} + 2 x - 2 = 0

x^{2} = x + 90

9 m^{2} + 6 m + 6 = 5

What are the solutions to the equation solvefor x,y^2+4x^2+16=0 ?
The solutions to the equation solvefor x,y^2+4x^2+16=0 are x=(sqrt(-y^2-16))/2 ,x=-(sqrt(-y^2-16))/2
Find the zeros of solvefor x,y^2+4x^2+16=0
The zeros of solvefor x,y^2+4x^2+16=0 are x=(sqrt(-y^2-16))/2 ,x=-(sqrt(-y^2-16))/2