What are the solutions to the equation 3(x^2-1)-2(x^2+2x)=5 ?

The solutions to the equation 3(x^2-1)-2(x^2+2x)=5 are x=2(1+sqrt(3)),x=2(1-sqrt(3))

Find the zeros of 3(x^2-1)-2(x^2+2x)=5

The zeros of 3(x^2-1)-2(x^2+2x)=5 are x=2(1+sqrt(3)),x=2(1-sqrt(3))

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3 (x^{2} - 1) - 2 (x^{2} + 2 x) = 5

x = 2 (1 + 3), x = 2 (1 - 3)

Decimal Notation

x = 5.46410 \dots, x = - 1.46410 \dots

Solution steps

3 (x^{2} - 1) - 2 (x^{2} + 2 x) = 5

Expand

3 (x^{2} - 1) - 2 (x^{2} + 2 x) : x^{2} - 4 x - 3

x^{2} - 4 x - 3 = 5

Move

5

to the left side

x^{2} - 4 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 8) = 43

x_{1, 2} = \frac{- ( - 4 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 3}{2 \cdot 1} : 2 (1 + 3)

x = \frac{- ( - 4 ) - 4 3}{2 \cdot 1} : 2 (1 - 3)

The solutions to the quadratic equation are:

x = 2 (1 + 3), x = 2 (1 - 3)

36 x^{2} - 81 = 0

x^{2} = - 10 x - 9

2 z^{2} + 5 z = 1

t, f = (t - 3) u^{2} (t) - (t - 2) u^{3} (t)

2 x^{2} = - 32

What are the solutions to the equation 3(x^2-1)-2(x^2+2x)=5 ?
The solutions to the equation 3(x^2-1)-2(x^2+2x)=5 are x=2(1+sqrt(3)),x=2(1-sqrt(3))
Find the zeros of 3(x^2-1)-2(x^2+2x)=5
The zeros of 3(x^2-1)-2(x^2+2x)=5 are x=2(1+sqrt(3)),x=2(1-sqrt(3))