What are the solutions to the equation 2x^2=-32 ?

The solutions to the equation 2x^2=-32 are x=4i,x=-4i

Find the zeros of 2x^2=-32

The zeros of 2x^2=-32 are x=4i,x=-4i

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2 x^{2} = - 32

x = 4 i, x = - 4 i

Solution steps

2 x^{2} = - 32

Divide both sides by

2

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

8 x^{2} - 15 x - 1 = - 7 x

6 x^{2} + 5 x - 2 = 0

- 2 x^{2} + 12 x - 14 = 0

0 = - x^{2} + 2

- x^{2} = 3 x - 10

What are the solutions to the equation 2x^2=-32 ?
The solutions to the equation 2x^2=-32 are x=4i,x=-4i
Find the zeros of 2x^2=-32
The zeros of 2x^2=-32 are x=4i,x=-4i