What are the solutions to the equation -x^2-25x+100=0 ?

The solutions to the equation -x^2-25x+100=0 are x=-(25+5sqrt(41))/2 ,x=(5sqrt(41)-25)/2

Find the zeros of -x^2-25x+100=0

The zeros of -x^2-25x+100=0 are x=-(25+5sqrt(41))/2 ,x=(5sqrt(41)-25)/2

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- x^{2} - 25 x + 100 = 0

x = - \frac{25 + 5 41}{2}, x = \frac{5 41 - 25}{2}

Decimal Notation

x = - 28.50781 \dots, x = 3.50781 \dots

Solution steps

- x^{2} - 25 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 ( - 1 ) \cdot 100}{2 ( - 1 )}

(- 25)^{2} - 4 (- 1) \cdot 100 = 541

x_{1, 2} = \frac{- ( - 25 ) \pm 5 41}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 5 41}{2 ( - 1 )}, x_{2} = \frac{- ( - 25 ) - 5 41}{2 ( - 1 )}

x = \frac{- ( - 25 ) + 5 41}{2 ( - 1 )} : - \frac{25 + 5 41}{2}

x = \frac{- ( - 25 ) - 5 41}{2 ( - 1 )} : \frac{5 41 - 25}{2}

The solutions to the quadratic equation are:

x = - \frac{25 + 5 41}{2}, x = \frac{5 41 - 25}{2}

- 2 x (3 x - 2) = - 2

5 x - 2 x^{2} = 0

(x + 4) (2 x - 1) - 1 = - 3 x (x + 2)

(x - 5) (x + 1) = 2 (x - 2)^{2}

x^{2} = (x - 2)^{2} + (x - 9)^{2}

What are the solutions to the equation -x^2-25x+100=0 ?
The solutions to the equation -x^2-25x+100=0 are x=-(25+5sqrt(41))/2 ,x=(5sqrt(41)-25)/2
Find the zeros of -x^2-25x+100=0
The zeros of -x^2-25x+100=0 are x=-(25+5sqrt(41))/2 ,x=(5sqrt(41)-25)/2