What are the solutions to the equation 4m^2+m-3=0 ?

The solutions to the equation 4m^2+m-3=0 are m= 3/4 ,m=-1

Find the zeros of 4m^2+m-3=0

The zeros of 4m^2+m-3=0 are m= 3/4 ,m=-1

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4 m^{2} + m - 3 = 0

m = \frac{3}{4}, m = - 1

Decimal Notation

m = 0.75, m = - 1

Solution steps

4 m^{2} + m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 3) = 7

m_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 1 + 7}{2 \cdot 4}, m_{2} = \frac{- 1 - 7}{2 \cdot 4}

m = \frac{- 1 + 7}{2 \cdot 4} : \frac{3}{4}

m = \frac{- 1 - 7}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

m = \frac{3}{4}, m = - 1

f, f = 0

x^{2} - 12 x + 48 = 0

2 x^{2} - x + 1

25 x^{2} + 30 x = 12

5 x^{2} - 360 x = 0

What are the solutions to the equation 4m^2+m-3=0 ?
The solutions to the equation 4m^2+m-3=0 are m= 3/4 ,m=-1
Find the zeros of 4m^2+m-3=0
The zeros of 4m^2+m-3=0 are m= 3/4 ,m=-1