What are the solutions to the equation k^2+3k-18=0 ?

The solutions to the equation k^2+3k-18=0 are k=3,k=-6

Find the zeros of k^2+3k-18=0

The zeros of k^2+3k-18=0 are k=3,k=-6

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k^{2} + 3 k - 18 = 0

k = 3, k = - 6

Solution steps

k^{2} + 3 k - 18 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

k_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 3 + 9}{2 \cdot 1}, k_{2} = \frac{- 3 - 9}{2 \cdot 1}

k = \frac{- 3 + 9}{2 \cdot 1} : 3

k = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

k = 3, k = - 6

x^{2} + 8 x + 16 = 0

x^{2} + x = \frac{7}{4}

x, x^{2} y = y - 7

(x + 5) (x - 9) = 0

x, z = 2 x^{2} + 4 x + y^{2} - 2 y + 3

What are the solutions to the equation k^2+3k-18=0 ?
The solutions to the equation k^2+3k-18=0 are k=3,k=-6
Find the zeros of k^2+3k-18=0
The zeros of k^2+3k-18=0 are k=3,k=-6