What are the solutions to the equation (x+5)(x-9)=0 ?

The solutions to the equation (x+5)(x-9)=0 are x=-5,x=9

Find the zeros of (x+5)(x-9)=0

The zeros of (x+5)(x-9)=0 are x=-5,x=9

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(x + 5) (x - 9) = 0

x = - 5, x = 9

Solution steps

(x + 5) (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x - 9 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x - 9 = 0 : x = 9

The solutions to the quadratic equation are:

x = - 5, x = 9

x, z = 2 x^{2} + 4 x + y^{2} - 2 y + 3

x^{2} + 3 x - 4 = 0

x^{2} + 20 = 5 x

x^{2} + 17 x - 18 = 0

(x - 4)^{2} - 13 (x - 4) + 36 = 0

What are the solutions to the equation (x+5)(x-9)=0 ?
The solutions to the equation (x+5)(x-9)=0 are x=-5,x=9
Find the zeros of (x+5)(x-9)=0
The zeros of (x+5)(x-9)=0 are x=-5,x=9