What are the solutions to the equation x^2+17x-18=0 ?

The solutions to the equation x^2+17x-18=0 are x=1,x=-18

Find the zeros of x^2+17x-18=0

The zeros of x^2+17x-18=0 are x=1,x=-18

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x^{2} + 17 x - 18 = 0

x = 1, x = - 18

Solution steps

x^{2} + 17 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot (- 18) = 19

x_{1, 2} = \frac{- 17 \pm 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 19}{2 \cdot 1}, x_{2} = \frac{- 17 - 19}{2 \cdot 1}

x = \frac{- 17 + 19}{2 \cdot 1} : 1

x = \frac{- 17 - 19}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

x = 1, x = - 18

(x - 4)^{2} - 13 (x - 4) + 36 = 0

1 - 2 x + x^{2} = 2 x + 1

x, y = (x - y)^{2}

4 - 25 x^{2} = 0

x^{2} - 2 x + 10

What are the solutions to the equation x^2+17x-18=0 ?
The solutions to the equation x^2+17x-18=0 are x=1,x=-18
Find the zeros of x^2+17x-18=0
The zeros of x^2+17x-18=0 are x=1,x=-18