What are the solutions to the equation 1-4x(1-x)=0 ?

The solutions to the equation 1-4x(1-x)=0 are x= 1/2

Find the zeros of 1-4x(1-x)=0

The zeros of 1-4x(1-x)=0 are x= 1/2

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1 - 4 x (1 - x) = 0

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

1 - 4 x (1 - x) = 0

Expand

1 - 4 x (1 - x) : 1 - 4 x + 4 x^{2}

1 - 4 x + 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

7 a^{2} - 19 a + 10 = 0

- 2 x^{2} + 8 x - 4

x^{2} - 8 x - 9 = 0

a^{2} + 3^{2} = 4^{2}

(x + 2) (x - 3) = 5

What are the solutions to the equation 1-4x(1-x)=0 ?
The solutions to the equation 1-4x(1-x)=0 are x= 1/2
Find the zeros of 1-4x(1-x)=0
The zeros of 1-4x(1-x)=0 are x= 1/2