What are the solutions to the equation x^2+21x+20=0 ?

The solutions to the equation x^2+21x+20=0 are x=-1,x=-20

Find the zeros of x^2+21x+20=0

The zeros of x^2+21x+20=0 are x=-1,x=-20

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x^{2} + 21 x + 20 = 0

x = - 1, x = - 20

Solution steps

x^{2} + 21 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

2 1^{2} - 4 \cdot 1 \cdot 20 = 19

x_{1, 2} = \frac{- 21 \pm 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 21 + 19}{2 \cdot 1}, x_{2} = \frac{- 21 - 19}{2 \cdot 1}

x = \frac{- 21 + 19}{2 \cdot 1} : - 1

x = \frac{- 21 - 19}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

x = - 1, x = - 20

x^{2} + 11 x + 5 = 0

x, 7 x - y + 3 x y = x^{2} + y^{2}

(4 + x) (5 - 2 x) = (2 x + 1) (x - 2)

x, 6 x^{2} - y^{2} + 24 x y - 12 x + 26 y + 11 = 0

5^{2} + 4^{2} = x^{2}

What are the solutions to the equation x^2+21x+20=0 ?
The solutions to the equation x^2+21x+20=0 are x=-1,x=-20
Find the zeros of x^2+21x+20=0
The zeros of x^2+21x+20=0 are x=-1,x=-20