What are the solutions to the equation x^2+11x+5=0 ?

The solutions to the equation x^2+11x+5=0 are x=(-11+sqrt(101))/2 ,x=(-11-sqrt(101))/2

Find the zeros of x^2+11x+5=0

The zeros of x^2+11x+5=0 are x=(-11+sqrt(101))/2 ,x=(-11-sqrt(101))/2

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x^{2} + 11 x + 5 = 0

x = \frac{- 11 + 101}{2}, x = \frac{- 11 - 101}{2}

Decimal Notation

x = - 0.47506 \dots, x = - 10.52493 \dots

Solution steps

x^{2} + 11 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 5 = 101

x_{1, 2} = \frac{- 11 \pm 101}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 101}{2 \cdot 1}, x_{2} = \frac{- 11 - 101}{2 \cdot 1}

x = \frac{- 11 + 101}{2 \cdot 1} : \frac{- 11 + 101}{2}

x = \frac{- 11 - 101}{2 \cdot 1} : \frac{- 11 - 101}{2}

The solutions to the quadratic equation are:

x = \frac{- 11 + 101}{2}, x = \frac{- 11 - 101}{2}

x, 7 x - y + 3 x y = x^{2} + y^{2}

(4 + x) (5 - 2 x) = (2 x + 1) (x - 2)

x, 6 x^{2} - y^{2} + 24 x y - 12 x + 26 y + 11 = 0

5^{2} + 4^{2} = x^{2}

7 x^{2} - 2 x - 8 = 0

What are the solutions to the equation x^2+11x+5=0 ?
The solutions to the equation x^2+11x+5=0 are x=(-11+sqrt(101))/2 ,x=(-11-sqrt(101))/2
Find the zeros of x^2+11x+5=0
The zeros of x^2+11x+5=0 are x=(-11+sqrt(101))/2 ,x=(-11-sqrt(101))/2