What are the solutions to the equation y^2-7y+6=0 ?

The solutions to the equation y^2-7y+6=0 are y=6,y=1

Find the zeros of y^2-7y+6=0

The zeros of y^2-7y+6=0 are y=6,y=1

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y^{2} - 7 y + 6 = 0

y = 6, y = 1

Solution steps

y^{2} - 7 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 6 = 5

y_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 1}, y_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 1}

y = \frac{- ( - 7 ) + 5}{2 \cdot 1} : 6

y = \frac{- ( - 7 ) - 5}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

y = 6, y = 1

2 x^{2} - 15 x + 13 = 1 - x^{2}

3^{2} + b^{2} = 7^{2}

2 x^{2} - 5 x + 67 = 0

3 x^{2} + 6 x = 8

x^{2} - \frac{1}{6} x - \frac{1}{6} = 0

What are the solutions to the equation y^2-7y+6=0 ?
The solutions to the equation y^2-7y+6=0 are y=6,y=1
Find the zeros of y^2-7y+6=0
The zeros of y^2-7y+6=0 are y=6,y=1