What are the solutions to the equation -3x^2-50x-243=4x ?

The solutions to the equation -3x^2-50x-243=4x are x=-9

Find the zeros of -3x^2-50x-243=4x

The zeros of -3x^2-50x-243=4x are x=-9

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- 3 x^{2} - 50 x - 243 = 4 x

x = - 9

Solution steps

- 3 x^{2} - 50 x - 243 = 4 x

Move

4 x

to the left side

- 3 x^{2} - 54 x - 243 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 54 ) \pm ( - 54 ) ^{2} - 4 ( - 3 ) ( - 243 )}{2 ( - 3 )}

(- 54)^{2} - 4 (- 3) (- 243) = 0

x_{1, 2} = \frac{- ( - 54 ) \pm 0}{2 ( - 3 )}

x = \frac{- ( - 54 )}{2 ( - 3 )}

\frac{- ( - 54 )}{2 ( - 3 )} = - 9

x = - 9

The solution to the quadratic equation is:

x = - 9

n^{2} - 3 n - 4 = 0

2.5 x^{2} - 2.5 x = 0

6 x^{2} + 4 x = - 11

x^{2} + 8 x = - 17

2 x^{2} = 7

What are the solutions to the equation -3x^2-50x-243=4x ?
The solutions to the equation -3x^2-50x-243=4x are x=-9
Find the zeros of -3x^2-50x-243=4x
The zeros of -3x^2-50x-243=4x are x=-9