What are the solutions to the equation a^2-a+2=0 ?

The solutions to the equation a^2-a+2=0 are a= 1/2+i(sqrt(7))/2 ,a= 1/2-i(sqrt(7))/2

Find the zeros of a^2-a+2=0

The zeros of a^2-a+2=0 are a= 1/2+i(sqrt(7))/2 ,a= 1/2-i(sqrt(7))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a^{2} - a + 2 = 0

a = \frac{1}{2} + i \frac{7}{2}, a = \frac{1}{2} - i \frac{7}{2}

Solution steps

a^{2} - a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 2 : 7 i

a_{1, 2} = \frac{- ( - 1 ) \pm 7 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 7 i}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 7 i}{2 \cdot 1}

a = \frac{- ( - 1 ) + 7 i}{2 \cdot 1} : \frac{1}{2} + i \frac{7}{2}

a = \frac{- ( - 1 ) - 7 i}{2 \cdot 1} : \frac{1}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

a = \frac{1}{2} + i \frac{7}{2}, a = \frac{1}{2} - i \frac{7}{2}

b^{2} = 64

24 x - 6 x^{2} = 0

(n - 7)^{2} = 2 n

x^{2} + 2 x - 5 = 0

6 x^{2} - 8 x - 30 = 0

What are the solutions to the equation a^2-a+2=0 ?
The solutions to the equation a^2-a+2=0 are a= 1/2+i(sqrt(7))/2 ,a= 1/2-i(sqrt(7))/2
Find the zeros of a^2-a+2=0
The zeros of a^2-a+2=0 are a= 1/2+i(sqrt(7))/2 ,a= 1/2-i(sqrt(7))/2