What are the solutions to the equation 1/4 x^2+3x=x-4 ?

The solutions to the equation 1/4 x^2+3x=x-4 are x=-4

Find the zeros of 1/4 x^2+3x=x-4

The zeros of 1/4 x^2+3x=x-4 are x=-4

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\frac{1}{4} x^{2} + 3 x = x - 4

x = - 4

Solution steps

\frac{1}{4} x^{2} + 3 x = x - 4

Multiply both sides by

4

x^{2} + 12 x = 4 x - 16

Move

16

to the left side

x^{2} + 12 x + 16 = 4 x

Move

4 x

to the left side

x^{2} + 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

x = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

- x^{2} + 8 x + 1 = 0

x^{2} - x = 7

x^{2} + 12 x - 18 = 0

90 x^{2} + 11 x - 2 = 0

x^{2} + 2 x - 31 = 0

What are the solutions to the equation 1/4 x^2+3x=x-4 ?
The solutions to the equation 1/4 x^2+3x=x-4 are x=-4
Find the zeros of 1/4 x^2+3x=x-4
The zeros of 1/4 x^2+3x=x-4 are x=-4