What are the solutions to the equation x^2-20x-6=-3 ?

The solutions to the equation x^2-20x-6=-3 are x=10+sqrt(103),x=10-sqrt(103)

Find the zeros of x^2-20x-6=-3

The zeros of x^2-20x-6=-3 are x=10+sqrt(103),x=10-sqrt(103)

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x^{2} - 20 x - 6 = - 3

x = 10 + 103, x = 10 - 103

Decimal Notation

x = 20.14889 \dots, x = - 0.14889 \dots

Solution steps

x^{2} - 20 x - 6 = - 3

Move

3

to the left side

x^{2} - 20 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot (- 3) = 2103

x_{1, 2} = \frac{- ( - 20 ) \pm 2 103}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 103}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2 103}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2 103}{2 \cdot 1} : 10 + 103

x = \frac{- ( - 20 ) - 2 103}{2 \cdot 1} : 10 - 103

The solutions to the quadratic equation are:

x = 10 + 103, x = 10 - 103

s^{2} = 169

\frac{x ^{2}}{2} + \frac{4 x}{3} = 6

x^{2} + 9 x + 16 = 2 x + 6

5 x^{2} - 7 x + 4 = 0

9 x^{2} = 63 x

What are the solutions to the equation x^2-20x-6=-3 ?
The solutions to the equation x^2-20x-6=-3 are x=10+sqrt(103),x=10-sqrt(103)
Find the zeros of x^2-20x-6=-3
The zeros of x^2-20x-6=-3 are x=10+sqrt(103),x=10-sqrt(103)