What are the solutions to the equation v^2+2v-15=0 ?

The solutions to the equation v^2+2v-15=0 are v=3,v=-5

Find the zeros of v^2+2v-15=0

The zeros of v^2+2v-15=0 are v=3,v=-5

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v^{2} + 2 v - 15 = 0

v = 3, v = - 5

Solution steps

v^{2} + 2 v - 15 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

v_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 2 + 8}{2 \cdot 1}, v_{2} = \frac{- 2 - 8}{2 \cdot 1}

v = \frac{- 2 + 8}{2 \cdot 1} : 3

v = \frac{- 2 - 8}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

v = 3, v = - 5

6 x^{2} + 2 x - 8 = 0

x^{2} - 81 = 0

4 (x^{2} + 1) = 3 (x^{2} + 3) + 4

4 x^{2} - 16 x

0 = 3 x^{2} - 8 x - 16

What are the solutions to the equation v^2+2v-15=0 ?
The solutions to the equation v^2+2v-15=0 are v=3,v=-5
Find the zeros of v^2+2v-15=0
The zeros of v^2+2v-15=0 are v=3,v=-5