What are the solutions to the equation 4x^2=-6x ?

The solutions to the equation 4x^2=-6x are x=0,x=-3/2

Find the zeros of 4x^2=-6x

The zeros of 4x^2=-6x are x=0,x=-3/2

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4 x^{2} = - 6 x

x = 0, x = - \frac{3}{2}

Decimal Notation

x = 0, x = - 1.5

Solution steps

4 x^{2} = - 6 x

Move

6 x

to the left side

4 x^{2} + 6 x = 0

Factor

4 x^{2} + 6 x : 2 x (2 x + 3)

2 x (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 3 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{3}{2}

10 b^{2} - 10 = - 141

x (x - 56) = 0

x, y^{2} = 4 x^{2}

5 x - 24 = - x^{2}

y = 0.00249 (1 - \frac{0.5714 - 2000 y}{- 2})^{2}

What are the solutions to the equation 4x^2=-6x ?
The solutions to the equation 4x^2=-6x are x=0,x=-3/2
Find the zeros of 4x^2=-6x
The zeros of 4x^2=-6x are x=0,x=-3/2