What are the solutions to the equation (2x-1/2)^2=4 ?

The solutions to the equation (2x-1/2)^2=4 are x= 5/4 ,x=-3/4

Find the zeros of (2x-1/2)^2=4

The zeros of (2x-1/2)^2=4 are x= 5/4 ,x=-3/4

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(2 x - \frac{1}{2})^{2} = 4

x = \frac{5}{4}, x = - \frac{3}{4}

Decimal Notation

x = 1.25, x = - 0.75

Solution steps

(2 x - \frac{1}{2})^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - \frac{1}{2} = 4 : x = \frac{5}{4}

Solve

2 x - \frac{1}{2} = - 4 : x = - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = - \frac{3}{4}

(k - 4) (k - 9) = 0

x^{2} = 9 x

- 5 x^{2} + 210 x + 1 = 2161

- 4 x^{2} - 2 x + 1 = 0

x, f = x^{2} + k

What are the solutions to the equation (2x-1/2)^2=4 ?
The solutions to the equation (2x-1/2)^2=4 are x= 5/4 ,x=-3/4
Find the zeros of (2x-1/2)^2=4
The zeros of (2x-1/2)^2=4 are x= 5/4 ,x=-3/4