What are the solutions to the equation -2x^2+108x+1=1009 ?

The solutions to the equation -2x^2+108x+1=1009 are x=12,x=42

Find the zeros of -2x^2+108x+1=1009

The zeros of -2x^2+108x+1=1009 are x=12,x=42

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- 2 x^{2} + 108 x + 1 = 1009

x = 12, x = 42

Solution steps

- 2 x^{2} + 108 x + 1 = 1009

Move

1009

to the left side

- 2 x^{2} + 108 x - 1008 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 108 \pm 10 8 ^{2} - 4 ( - 2 ) ( - 1008 )}{2 ( - 2 )}

10 8^{2} - 4 (- 2) (- 1008) = 60

x_{1, 2} = \frac{- 108 \pm 60}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 108 + 60}{2 ( - 2 )}, x_{2} = \frac{- 108 - 60}{2 ( - 2 )}

x = \frac{- 108 + 60}{2 ( - 2 )} : 12

x = \frac{- 108 - 60}{2 ( - 2 )} : 42

The solutions to the quadratic equation are:

x = 12, x = 42

16 x^{2} - 88 x + 121 = 0

0 = - 16 (t)^{2} + 50 (t) + 10

9 x^{2} + 7 x - 2 = 0

- 3 x^{2} - 9 x - 1 = 0

w^{2} - 2 w = 0

What are the solutions to the equation -2x^2+108x+1=1009 ?
The solutions to the equation -2x^2+108x+1=1009 are x=12,x=42
Find the zeros of -2x^2+108x+1=1009
The zeros of -2x^2+108x+1=1009 are x=12,x=42