What are the solutions to the equation 5x^2+20x-25=0 ?

The solutions to the equation 5x^2+20x-25=0 are x=1,x=-5

Find the zeros of 5x^2+20x-25=0

The zeros of 5x^2+20x-25=0 are x=1,x=-5

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5 x^{2} + 20 x - 25 = 0

x = 1, x = - 5

Solution steps

5 x^{2} + 20 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 ( - 25 )}{2 \cdot 5}

2 0^{2} - 4 \cdot 5 (- 25) = 30

x_{1, 2} = \frac{- 20 \pm 30}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 20 + 30}{2 \cdot 5}, x_{2} = \frac{- 20 - 30}{2 \cdot 5}

x = \frac{- 20 + 30}{2 \cdot 5} : 1

x = \frac{- 20 - 30}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

0 = 36 x^{2} - 24 x

6 x^{2} + 4 x = 0

z, (z + 3)^{3} + (z - m)^{3} = 2 (z^{3} + 6 m^{3})

3 w^{2} + 27 w = 0

a, b a^{2} + 3 = N^{3}

What are the solutions to the equation 5x^2+20x-25=0 ?
The solutions to the equation 5x^2+20x-25=0 are x=1,x=-5
Find the zeros of 5x^2+20x-25=0
The zeros of 5x^2+20x-25=0 are x=1,x=-5