What are the solutions to the equation 2a^2-8a+3=0 ?

The solutions to the equation 2a^2-8a+3=0 are a=(4+sqrt(10))/2 ,a=(4-sqrt(10))/2

Find the zeros of 2a^2-8a+3=0

The zeros of 2a^2-8a+3=0 are a=(4+sqrt(10))/2 ,a=(4-sqrt(10))/2

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2 a^{2} - 8 a + 3 = 0

a = \frac{4 + 10}{2}, a = \frac{4 - 10}{2}

Decimal Notation

a = 3.58113 \dots, a = 0.41886 \dots

Solution steps

2 a^{2} - 8 a + 3 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 3 = 210

a_{1, 2} = \frac{- ( - 8 ) \pm 2 10}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- ( - 8 ) + 2 10}{2 \cdot 2}, a_{2} = \frac{- ( - 8 ) - 2 10}{2 \cdot 2}

a = \frac{- ( - 8 ) + 2 10}{2 \cdot 2} : \frac{4 + 10}{2}

a = \frac{- ( - 8 ) - 2 10}{2 \cdot 2} : \frac{4 - 10}{2}

The solutions to the quadratic equation are:

a = \frac{4 + 10}{2}, a = \frac{4 - 10}{2}

\frac{1}{4} x^{2} + 2 x + 4 = 0

x (x + 5) = 84

x, \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{25} = 1

(x + 1)^{2} = 24

4 x^{2} + 12 x - 9 = 0

What are the solutions to the equation 2a^2-8a+3=0 ?
The solutions to the equation 2a^2-8a+3=0 are a=(4+sqrt(10))/2 ,a=(4-sqrt(10))/2
Find the zeros of 2a^2-8a+3=0
The zeros of 2a^2-8a+3=0 are a=(4+sqrt(10))/2 ,a=(4-sqrt(10))/2