What are the solutions to the equation (x-1)(x-3)=-1 ?

The solutions to the equation (x-1)(x-3)=-1 are x=2

Find the zeros of (x-1)(x-3)=-1

The zeros of (x-1)(x-3)=-1 are x=2

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(x - 1) (x - 3) = - 1

x = 2

Solution steps

(x - 1) (x - 3) = - 1

Expand

(x - 1) (x - 3) : x^{2} - 4 x + 3

x^{2} - 4 x + 3 = - 1

Move

1

to the left side

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

6 a^{2} - 4 a - 22 = 0

x, 3 x^{2} + 2 x y + y^{2} = 1

- 3 x^{2} + 2 x + 3 = 0

- x^{2} + 12 x - 32 = 0

x^{2} = 9^{2} + 1 2^{2}

What are the solutions to the equation (x-1)(x-3)=-1 ?
The solutions to the equation (x-1)(x-3)=-1 are x=2
Find the zeros of (x-1)(x-3)=-1
The zeros of (x-1)(x-3)=-1 are x=2