What are the solutions to the equation solvefor x,x^2-4x+5=0 ?

The solutions to the equation solvefor x,x^2-4x+5=0 are x=2+i,x=2-i

Find the zeros of solvefor x,x^2-4x+5=0

The zeros of solvefor x,x^2-4x+5=0 are x=2+i,x=2-i

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x, x^{2} - 4 x + 5 = 0

x = 2 + i, x = 2 - i

Solution steps

x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 i}{2 \cdot 1} : 2 + i

x = \frac{- ( - 4 ) - 2 i}{2 \cdot 1} : 2 - i

The solutions to the quadratic equation are:

x = 2 + i, x = 2 - i

v, \frac{1}{2} m v^{2} = m g h

x^{2} + 0.13 x + 0.0032 = 0

y, 2 x^{3} + x^{2} y + y^{2} = 4

0 = 3 x^{2} - 12 x + 12

1 2^{2} + 1 3^{2} = c^{2}

What are the solutions to the equation solvefor x,x^2-4x+5=0 ?
The solutions to the equation solvefor x,x^2-4x+5=0 are x=2+i,x=2-i
Find the zeros of solvefor x,x^2-4x+5=0
The zeros of solvefor x,x^2-4x+5=0 are x=2+i,x=2-i