What are the solutions to the equation -x^2-6x+8=0 ?

The solutions to the equation -x^2-6x+8=0 are x=-3-sqrt(17),x=sqrt(17)-3

Find the zeros of -x^2-6x+8=0

The zeros of -x^2-6x+8=0 are x=-3-sqrt(17),x=sqrt(17)-3

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- x^{2} - 6 x + 8 = 0

x = - 3 - 17, x = 17 - 3

Decimal Notation

x = - 7.12310 \dots, x = 1.12310 \dots

Solution steps

- x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 8}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 8 = 217

x_{1, 2} = \frac{- ( - 6 ) \pm 2 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 17}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 2 17}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 2 17}{2 ( - 1 )} : - 3 - 17

x = \frac{- ( - 6 ) - 2 17}{2 ( - 1 )} : 17 - 3

The solutions to the quadratic equation are:

x = - 3 - 17, x = 17 - 3

36 x^{2} - 24 x + 4 = 81

3 - x^{2} = 3 - 3 x

m^{2} - 10 m + 16 = 0

c^{2} = 9

- 3 x^{2} + 5 = 0

What are the solutions to the equation -x^2-6x+8=0 ?
The solutions to the equation -x^2-6x+8=0 are x=-3-sqrt(17),x=sqrt(17)-3
Find the zeros of -x^2-6x+8=0
The zeros of -x^2-6x+8=0 are x=-3-sqrt(17),x=sqrt(17)-3