What are the solutions to the equation -4.9t^2+19.6t+58.8=0 ?

The solutions to the equation -4.9t^2+19.6t+58.8=0 are t=-2,t=6

Find the zeros of -4.9t^2+19.6t+58.8=0

The zeros of -4.9t^2+19.6t+58.8=0 are t=-2,t=6

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- 4.9 t^{2} + 19.6 t + 58.8 = 0

t = - 2, t = 6

Solution steps

- 4.9 t^{2} + 19.6 t + 58.8 = 0

Multiply both sides by

10

- 49 t^{2} + 196 t + 588 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 196 \pm 19 6 ^{2} - 4 ( - 49 ) \cdot 588}{2 ( - 49 )}

19 6^{2} - 4 (- 49) \cdot 588 = 392

t_{1, 2} = \frac{- 196 \pm 392}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 196 + 392}{2 ( - 49 )}, t_{2} = \frac{- 196 - 392}{2 ( - 49 )}

t = \frac{- 196 + 392}{2 ( - 49 )} : - 2

t = \frac{- 196 - 392}{2 ( - 49 )} : 6

The solutions to the quadratic equation are:

t = - 2, t = 6

x^{2} - 2 x - 36 = 0

4 x^{2} + 36 x + 85 = 0

k^{2} + 3 k + 2 = 0

2 5^{2} = 1 5^{2} + x^{2}

9 m^{2} + 54 = 5

What are the solutions to the equation -4.9t^2+19.6t+58.8=0 ?
The solutions to the equation -4.9t^2+19.6t+58.8=0 are t=-2,t=6
Find the zeros of -4.9t^2+19.6t+58.8=0
The zeros of -4.9t^2+19.6t+58.8=0 are t=-2,t=6