What are the solutions to the equation 4x^2-8x-9=0 ?

The solutions to the equation 4x^2-8x-9=0 are x=(2+sqrt(13))/2 ,x=(2-sqrt(13))/2

Find the zeros of 4x^2-8x-9=0

The zeros of 4x^2-8x-9=0 are x=(2+sqrt(13))/2 ,x=(2-sqrt(13))/2

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4 x^{2} - 8 x - 9 = 0

x = \frac{2 + 13}{2}, x = \frac{2 - 13}{2}

Decimal Notation

x = 2.80277 \dots, x = - 0.80277 \dots

Solution steps

4 x^{2} - 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 9) = 413

x_{1, 2} = \frac{- ( - 8 ) \pm 4 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 13}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 13}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 13}{2 \cdot 4} : \frac{2 + 13}{2}

x = \frac{- ( - 8 ) - 4 13}{2 \cdot 4} : \frac{2 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 13}{2}, x = \frac{2 - 13}{2}

- 3 x^{2} - 16 x + 84 = 0

125 - x^{2} = x^{2} + 15 x

x^{2} \cdot 3 = 33

x^{2} - 4 x + 10 = 0

r^{2} + 32 = 12 r

What are the solutions to the equation 4x^2-8x-9=0 ?
The solutions to the equation 4x^2-8x-9=0 are x=(2+sqrt(13))/2 ,x=(2-sqrt(13))/2
Find the zeros of 4x^2-8x-9=0
The zeros of 4x^2-8x-9=0 are x=(2+sqrt(13))/2 ,x=(2-sqrt(13))/2