What are the solutions to the equation (x+3)(x-4)=8 ?

The solutions to the equation (x+3)(x-4)=8 are x=5,x=-4

Find the zeros of (x+3)(x-4)=8

The zeros of (x+3)(x-4)=8 are x=5,x=-4

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(x + 3) (x - 4) = 8

x = 5, x = - 4

Solution steps

(x + 3) (x - 4) = 8

Expand

(x + 3) (x - 4) : x^{2} - x - 12

x^{2} - x - 12 = 8

Move

8

to the left side

x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

x = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

x = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

2 r^{2} + 2 r + 1 = 0

x^{2} - 14 x + 229 = 0

t, p = 3 t^{2} + 10 t - 900

15 x^{2} - 12 = - 8 x

- 0.2 x^{2} + 220 = 0.1 x^{2} + 8 x + 110

What are the solutions to the equation (x+3)(x-4)=8 ?
The solutions to the equation (x+3)(x-4)=8 are x=5,x=-4
Find the zeros of (x+3)(x-4)=8
The zeros of (x+3)(x-4)=8 are x=5,x=-4