What are the solutions to the equation (-(sqrt(11))/4)^2+y^2=1 ?

The solutions to the equation (-(sqrt(11))/4)^2+y^2=1 are y=(sqrt(5))/4 ,y=-(sqrt(5))/4

Find the zeros of (-(sqrt(11))/4)^2+y^2=1

The zeros of (-(sqrt(11))/4)^2+y^2=1 are y=(sqrt(5))/4 ,y=-(sqrt(5))/4

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(- \frac{11}{4})^{2} + y^{2} = 1

y = \frac{5}{4}, y = - \frac{5}{4}

Decimal Notation

y = 0.55901 \dots, y = - 0.55901 \dots

Solution steps

(- \frac{11}{4})^{2} + y^{2} = 1

Expand

(- \frac{11}{4})^{2} + y^{2} : \frac{11}{16} + y^{2}

\frac{11}{16} + y^{2} = 1

Move

\frac{11}{16}

to the right side

y^{2} = 1 - \frac{11}{16}

Simplify

1 - \frac{11}{16} : \frac{5}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{5}{16}, y = - \frac{5}{16}

\frac{5}{16} = \frac{5}{4}

- \frac{5}{16} = - \frac{5}{4}

y = \frac{5}{4}, y = - \frac{5}{4}

x^{2} + 9 x + 18 = 0

x^{2} - 7.2 x + 12.8 = 0

5 x = (2 x + 1)^{2}

- 4.9 t^{2} + 11 t + 500 = 0

- x^{2} - 4 x + 5

What are the solutions to the equation (-(sqrt(11))/4)^2+y^2=1 ?
The solutions to the equation (-(sqrt(11))/4)^2+y^2=1 are y=(sqrt(5))/4 ,y=-(sqrt(5))/4
Find the zeros of (-(sqrt(11))/4)^2+y^2=1
The zeros of (-(sqrt(11))/4)^2+y^2=1 are y=(sqrt(5))/4 ,y=-(sqrt(5))/4