What are the solutions to the equation 3x^2+3x-5=0 ?

The solutions to the equation 3x^2+3x-5=0 are x=(-3+sqrt(69))/6 ,x=(-3-sqrt(69))/6

Find the zeros of 3x^2+3x-5=0

The zeros of 3x^2+3x-5=0 are x=(-3+sqrt(69))/6 ,x=(-3-sqrt(69))/6

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3 x^{2} + 3 x - 5 = 0

x = \frac{- 3 + 69}{6}, x = \frac{- 3 - 69}{6}

Decimal Notation

x = 0.88443 \dots, x = - 1.88443 \dots

Solution steps

3 x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 5) = 69

x_{1, 2} = \frac{- 3 \pm 69}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 69}{2 \cdot 3}, x_{2} = \frac{- 3 - 69}{2 \cdot 3}

x = \frac{- 3 + 69}{2 \cdot 3} : \frac{- 3 + 69}{6}

x = \frac{- 3 - 69}{2 \cdot 3} : \frac{- 3 - 69}{6}

The solutions to the quadratic equation are:

x = \frac{- 3 + 69}{6}, x = \frac{- 3 - 69}{6}

9^{6}

2 x - 8 + x - 5 > 3 x - 9

\frac{( x - 3 ) ^{2}}{2} - x + x^{2} = x - (x - 2)

3 c + 10 = 28

3 q - 2 \leq - 10 or 3 q - 2 > 10

What are the solutions to the equation 3x^2+3x-5=0 ?
The solutions to the equation 3x^2+3x-5=0 are x=(-3+sqrt(69))/6 ,x=(-3-sqrt(69))/6
Find the zeros of 3x^2+3x-5=0
The zeros of 3x^2+3x-5=0 are x=(-3+sqrt(69))/6 ,x=(-3-sqrt(69))/6