What are the solutions to the equation n^2-n-6=0 ?

The solutions to the equation n^2-n-6=0 are n=3,n=-2

Find the zeros of n^2-n-6=0

The zeros of n^2-n-6=0 are n=3,n=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{2} - n - 6 = 0

n = 3, n = - 2

Solution steps

n^{2} - n - 6 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

n_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, n_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

n = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

n = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

n = 3, n = - 2

2 x^{2} + 15 = - 11 x

x^{2} - 19 x - 39 = 0

3 x^{2} + 4 x - 2

a x^{2} + x = 7 x

q^{2} + 10 q + 25 = 0

What are the solutions to the equation n^2-n-6=0 ?
The solutions to the equation n^2-n-6=0 are n=3,n=-2
Find the zeros of n^2-n-6=0
The zeros of n^2-n-6=0 are n=3,n=-2