What are the solutions to the equation -2x^2-11x+12=0 ?

The solutions to the equation -2x^2-11x+12=0 are x=-(11+sqrt(217))/4 ,x=(sqrt(217)-11)/4

Find the zeros of -2x^2-11x+12=0

The zeros of -2x^2-11x+12=0 are x=-(11+sqrt(217))/4 ,x=(sqrt(217)-11)/4

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- 2 x^{2} - 11 x + 12 = 0

x = - \frac{11 + 217}{4}, x = \frac{217 - 11}{4}

Decimal Notation

x = - 6.43272 \dots, x = 0.93272 \dots

Solution steps

- 2 x^{2} - 11 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 ( - 2 ) \cdot 12}{2 ( - 2 )}

(- 11)^{2} - 4 (- 2) \cdot 12 = 217

x_{1, 2} = \frac{- ( - 11 ) \pm 217}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 217}{2 ( - 2 )}, x_{2} = \frac{- ( - 11 ) - 217}{2 ( - 2 )}

x = \frac{- ( - 11 ) + 217}{2 ( - 2 )} : - \frac{11 + 217}{4}

x = \frac{- ( - 11 ) - 217}{2 ( - 2 )} : \frac{217 - 11}{4}

The solutions to the quadratic equation are:

x = - \frac{11 + 217}{4}, x = \frac{217 - 11}{4}

x^{2} + 8 x = 0

m^{2} = 3 m - 2

2 (x - 3)^{2} = 24

(y + 2)^{2} = 0

x, x^{2} + y^{2} + 2 x + 4 y + 6 = 0

What are the solutions to the equation -2x^2-11x+12=0 ?
The solutions to the equation -2x^2-11x+12=0 are x=-(11+sqrt(217))/4 ,x=(sqrt(217)-11)/4
Find the zeros of -2x^2-11x+12=0
The zeros of -2x^2-11x+12=0 are x=-(11+sqrt(217))/4 ,x=(sqrt(217)-11)/4