What are the solutions to the equation 2(x-3)^2=24 ?

The solutions to the equation 2(x-3)^2=24 are x=2sqrt(3)+3,x=-2sqrt(3)+3

Find the zeros of 2(x-3)^2=24

The zeros of 2(x-3)^2=24 are x=2sqrt(3)+3,x=-2sqrt(3)+3

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2 (x - 3)^{2} = 24

x = 23 + 3, x = - 23 + 3

Decimal Notation

x = 6.46410 \dots, x = - 0.46410 \dots

Solution steps

2 (x - 3)^{2} = 24

Divide both sides by

2

(x - 3)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 12 : x = 23 + 3

Solve

x - 3 = - 12 : x = - 23 + 3

The solutions to the quadratic equation are:

x = 23 + 3, x = - 23 + 3

(y + 2)^{2} = 0

x, x^{2} + y^{2} + 2 x + 4 y + 6 = 0

a, x^{2} + x y + y^{2} = a^{2}

6 x^{2} + 18 x - 108 = 0

x, x^{2} + y^{2} + 8 y = - 16

What are the solutions to the equation 2(x-3)^2=24 ?
The solutions to the equation 2(x-3)^2=24 are x=2sqrt(3)+3,x=-2sqrt(3)+3
Find the zeros of 2(x-3)^2=24
The zeros of 2(x-3)^2=24 are x=2sqrt(3)+3,x=-2sqrt(3)+3