What are the solutions to the equation 6x^2+18x-108=0 ?

The solutions to the equation 6x^2+18x-108=0 are x=3,x=-6

Find the zeros of 6x^2+18x-108=0

The zeros of 6x^2+18x-108=0 are x=3,x=-6

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6 x^{2} + 18 x - 108 = 0

x = 3, x = - 6

Solution steps

6 x^{2} + 18 x - 108 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 6 ( - 108 )}{2 \cdot 6}

1 8^{2} - 4 \cdot 6 (- 108) = 54

x_{1, 2} = \frac{- 18 \pm 54}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 18 + 54}{2 \cdot 6}, x_{2} = \frac{- 18 - 54}{2 \cdot 6}

x = \frac{- 18 + 54}{2 \cdot 6} : 3

x = \frac{- 18 - 54}{2 \cdot 6} : - 6

The solutions to the quadratic equation are:

x = 3, x = - 6

x, x^{2} + y^{2} + 8 y = - 16

x^{2} + 2.5 x - 1.5 = 0

x^{(2)} + (\frac{x}{4})^{(2)} = 16

(3 x + 1) (x - 2) = 0

4 x^{2} - 16 x - 15 = 3 x^{2} - 24

What are the solutions to the equation 6x^2+18x-108=0 ?
The solutions to the equation 6x^2+18x-108=0 are x=3,x=-6
Find the zeros of 6x^2+18x-108=0
The zeros of 6x^2+18x-108=0 are x=3,x=-6