What are the solutions to the equation x(x+4)=165 ?

The solutions to the equation x(x+4)=165 are x=11,x=-15

Find the zeros of x(x+4)=165

The zeros of x(x+4)=165 are x=11,x=-15

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x (x + 4) = 165

x = 11, x = - 15

Solution steps

x (x + 4) = 165

Expand

x (x + 4) : x^{2} + 4 x

x^{2} + 4 x = 165

Move

165

to the left side

x^{2} + 4 x - 165 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 165 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 165) = 26

x_{1, 2} = \frac{- 4 \pm 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 26}{2 \cdot 1}, x_{2} = \frac{- 4 - 26}{2 \cdot 1}

x = \frac{- 4 + 26}{2 \cdot 1} : 11

x = \frac{- 4 - 26}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 11, x = - 15

x, f = 3 x^{2} - x + 52 f (- 3) - f (4)

- x^{2} + 8 x + 47 = 0

2 x^{2} + (m + 6) = m x

4 x^{2} - 4 x - 3

6 m^{2} + 13 m - 5 = 0

What are the solutions to the equation x(x+4)=165 ?
The solutions to the equation x(x+4)=165 are x=11,x=-15
Find the zeros of x(x+4)=165
The zeros of x(x+4)=165 are x=11,x=-15