What are the solutions to the equation 9x^2-x=1+x ?

The solutions to the equation 9x^2-x=1+x are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9

Find the zeros of 9x^2-x=1+x

The zeros of 9x^2-x=1+x are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9

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9 x^{2} - x = 1 + x

x = \frac{1 + 10}{9}, x = \frac{1 - 10}{9}

Decimal Notation

x = 0.46247 \dots, x = - 0.24025 \dots

Solution steps

9 x^{2} - x = 1 + x

Move

x

to the left side

9 x^{2} - 2 x = 1

Move

1

to the left side

9 x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

(- 2)^{2} - 4 \cdot 9 (- 1) = 210

x_{1, 2} = \frac{- ( - 2 ) \pm 2 10}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 10}{2 \cdot 9}, x_{2} = \frac{- ( - 2 ) - 2 10}{2 \cdot 9}

x = \frac{- ( - 2 ) + 2 10}{2 \cdot 9} : \frac{1 + 10}{9}

x = \frac{- ( - 2 ) - 2 10}{2 \cdot 9} : \frac{1 - 10}{9}

The solutions to the quadratic equation are:

x = \frac{1 + 10}{9}, x = \frac{1 - 10}{9}

(x - 5)^{2} = 15

x^{2} + 7 x = 14

s^{2} + 3 s + 2

- 3 - x^{2} = 24

(2 x + 5) (x - 4) = 0

What are the solutions to the equation 9x^2-x=1+x ?
The solutions to the equation 9x^2-x=1+x are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9
Find the zeros of 9x^2-x=1+x
The zeros of 9x^2-x=1+x are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9