What are the solutions to the equation -6x^2+6x+12=0 ?

The solutions to the equation -6x^2+6x+12=0 are x=-1,x=2

Find the zeros of -6x^2+6x+12=0

The zeros of -6x^2+6x+12=0 are x=-1,x=2

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- 6 x^{2} + 6 x + 12 = 0

x = - 1, x = 2

Solution steps

- 6 x^{2} + 6 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 6 ) \cdot 12}{2 ( - 6 )}

6^{2} - 4 (- 6) \cdot 12 = 18

x_{1, 2} = \frac{- 6 \pm 18}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 6 + 18}{2 ( - 6 )}, x_{2} = \frac{- 6 - 18}{2 ( - 6 )}

x = \frac{- 6 + 18}{2 ( - 6 )} : - 1

x = \frac{- 6 - 18}{2 ( - 6 )} : 2

The solutions to the quadratic equation are:

x = - 1, x = 2

x^{2} + 15 x + 16 = 0

x, x^{2} + 2 x - 15 = 0

x, x^{2} y + 4 x y - x^{2} + x + 4 y - 6 = 0

\frac{3 x ^{2}}{4} - 3 = 0

4 m^{2} + 4 m + 17 = 0

What are the solutions to the equation -6x^2+6x+12=0 ?
The solutions to the equation -6x^2+6x+12=0 are x=-1,x=2
Find the zeros of -6x^2+6x+12=0
The zeros of -6x^2+6x+12=0 are x=-1,x=2