What are the solutions to the equation x^2-2x+1=-6 ?

The solutions to the equation x^2-2x+1=-6 are x=1+sqrt(6)i,x=1-sqrt(6)i

Find the zeros of x^2-2x+1=-6

The zeros of x^2-2x+1=-6 are x=1+sqrt(6)i,x=1-sqrt(6)i

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x^{2} - 2 x + 1 = - 6

x = 1 + 6 i, x = 1 - 6 i

Solution steps

x^{2} - 2 x + 1 = - 6

Move

6

to the left side

x^{2} - 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 7 : 26 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 6 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 6 i}{2 \cdot 1} : 1 + 6 i

x = \frac{- ( - 2 ) - 2 6 i}{2 \cdot 1} : 1 - 6 i

The solutions to the quadratic equation are:

x = 1 + 6 i, x = 1 - 6 i

x^{2} - 51 = - 2 x

4 - x^{2} = \frac{1}{4} + x^{2}

- 4 = x^{2} - 4 x

6 x^{2} + 8 x

x^{2} + x - \frac{1}{4} = 0

What are the solutions to the equation x^2-2x+1=-6 ?
The solutions to the equation x^2-2x+1=-6 are x=1+sqrt(6)i,x=1-sqrt(6)i
Find the zeros of x^2-2x+1=-6
The zeros of x^2-2x+1=-6 are x=1+sqrt(6)i,x=1-sqrt(6)i