What are the solutions to the equation 0=4x^2-8x-5 ?

The solutions to the equation 0=4x^2-8x-5 are x= 5/2 ,x=-1/2

Find the zeros of 0=4x^2-8x-5

The zeros of 0=4x^2-8x-5 are x= 5/2 ,x=-1/2

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0 = 4 x^{2} - 8 x - 5

x = \frac{5}{2}, x = - \frac{1}{2}

Decimal Notation

x = 2.5, x = - 0.5

Solution steps

0 = 4 x^{2} - 8 x - 5

Switch sides

4 x^{2} - 8 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 5) = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 4}

x = \frac{- ( - 8 ) + 12}{2 \cdot 4} : \frac{5}{2}

x = \frac{- ( - 8 ) - 12}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{1}{2}

D, D^{2} y - Dy - 6 y = e^{2 x}

x, 3 x^{2} + 4 y^{2} - 6 x - 24 y + 39 = 0

x, x^{2} + 2 x + y^{2} - 6 y = c

A x^{2} + D x

3^{2} + 4^{2} = r^{2}

What are the solutions to the equation 0=4x^2-8x-5 ?
The solutions to the equation 0=4x^2-8x-5 are x= 5/2 ,x=-1/2
Find the zeros of 0=4x^2-8x-5
The zeros of 0=4x^2-8x-5 are x= 5/2 ,x=-1/2