What are the solutions to the equation 3^2+4^2=r^2 ?

The solutions to the equation 3^2+4^2=r^2 are r=5,r=-5

Find the zeros of 3^2+4^2=r^2

The zeros of 3^2+4^2=r^2 are r=5,r=-5

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3^{2} + 4^{2} = r^{2}

r = 5, r = - 5

Solution steps

3^{2} + 4^{2} = r^{2}

Switch sides

r^{2} = 3^{2} + 4^{2}

Simplify

3^{2} + 4^{2} : 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 25, r = - 25

25 = 5

- 25 = - 5

r = 5, r = - 5

5 x^{2} - 10 x + 7 = 0

x, 21 x^{2} + 6 x y + 13 y^{2} - 114 x + 34 y + 73 = 0

\frac{( 4 x - 3 ) ^{2}}{5} + \frac{( 3 x - 2 )}{25} = 0

- 6 x^{2} + 72 x - 162 = 0

- 3 x^{2} - 42 x - 51 = - 12 x

What are the solutions to the equation 3^2+4^2=r^2 ?
The solutions to the equation 3^2+4^2=r^2 are r=5,r=-5
Find the zeros of 3^2+4^2=r^2
The zeros of 3^2+4^2=r^2 are r=5,r=-5