What are the solutions to the equation x^2+6x-135=0 ?

The solutions to the equation x^2+6x-135=0 are x=9,x=-15

Find the zeros of x^2+6x-135=0

The zeros of x^2+6x-135=0 are x=9,x=-15

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x^{2} + 6 x - 135 = 0

x = 9, x = - 15

Solution steps

x^{2} + 6 x - 135 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 135 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 135) = 24

x_{1, 2} = \frac{- 6 \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 24}{2 \cdot 1}, x_{2} = \frac{- 6 - 24}{2 \cdot 1}

x = \frac{- 6 + 24}{2 \cdot 1} : 9

x = \frac{- 6 - 24}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 9, x = - 15

(2 - x)^{2} = 36

a, an = 1 + n - n^{2}

(2 x - 5)^{2} = (x - 6)^{2} + (2 x + 1) (2 x - 9)

x^{2} = \frac{1}{100}

2 x^{2} - 7 x + 3 = 0

What are the solutions to the equation x^2+6x-135=0 ?
The solutions to the equation x^2+6x-135=0 are x=9,x=-15
Find the zeros of x^2+6x-135=0
The zeros of x^2+6x-135=0 are x=9,x=-15